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whether the Δwheels were relatively inside out.) The rival good positions can then be scored by a more accurate method. Before we had time to work out the correct wheel-sliding table a cruder method was used. This cruder method is to evaluate
Denote the decibanage of a typical character of one wheel by x, so that its odds of being a dot are xy = 10x/10 and probability . Let p = ½ (1 + Π). Let the probability of having an x in a cell of the first wheel be px if the character is a cross. Then the probability of having an x if the character is a dot is θpx. Denote by x', θ', p'x' the corresponding functions for the second wheel. Then the probability of seeing an x opposite an x' if the relative position of the two wheels is correct and they are not relatively inside out is
½(px px' + θpx θ'p'x') | |
and if it is wrong | |
½ px(1 + θ) ½ p'x'(1 + θ') |
Therefore the factor obtained from one pair of entries in favour of the slide being correct is
The factor obtained from the complete comparison is
In order that this formula should not be misleading, it is necessary to allow for competition, because the correct wheel may have very good slides against itself. A table exists for accurate wheel-sliding with pip value 2/3 deciban (See R1, 97).
(d) Setting two messages in depth on Chi 1 and Chi 2.
Closely related to significance test 0 is the problem of attempting to set two messages in depth on chi 1 and chi 2 before either rectangle is converged: (R1, 75; R3, 28, 35). In order to show how close the relationship is, the problem can be attacked in the following way. Let each of the 1271 different relative settings of chi 1 and chi 2 be tried out. For each of
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